Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 136

Answer

$$x=0$$ $$x=2$$ $$x=-21$$

Work Step by Step

We have $$19x^2-42x=-x^3$$ Sending all the terns to the left side of the equation $$19x^2-42x+x^3=0$$ Factorizing $$x(x^2+19x-42)=0$$ $$x(x+21)(x-2)=0$$ Solving each parenthesis 1)$$x=0$$ 2)$$x+21=0$$ $$x=-21$$ 3)$$x-2=0$$ $$x=2$$
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