Answer
$$x=0$$
$$x=2$$
$$x=-21$$
Work Step by Step
We have $$19x^2-42x=-x^3$$
Sending all the terns to the left side of the equation $$19x^2-42x+x^3=0$$
Factorizing $$x(x^2+19x-42)=0$$ $$x(x+21)(x-2)=0$$
Solving each parenthesis 1)$$x=0$$
2)$$x+21=0$$ $$x=-21$$
3)$$x-2=0$$ $$x=2$$
