Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 137

Answer

$$x=0$$ $$x=1$$ $$x=-2$$

Work Step by Step

We have $$12x=6x^3+6x^2$$ Sending all the terms to one side $$6x^3+6x^2-12x=0$$ Factorizing $$6x(x^2+x-2)=0$$ $$6x(x+2)(x-1)=0$$ Solving each parenthesis 1)$$6x=0$$ $$x=0$$ 2)$$x+2=0$$ $$x=-2$$ 3)$$x-1=0$$ $$x=1$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.