Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 133

Answer

$$x=-4$$ $$x=1$$

Work Step by Step

We have $$3x^2+2x=12-7x$$ Sending all the terms to the left side of the equation $$3x^2+2x+7x-12=0$$ $$3x^2+9x-12=0$$ Factorizing $$(3x+12)(x-1)=0$$ Solving each parenthesis 1) $$3x+12=0$$ $$3x=-12$$ $$x=-4$$ 2) $$x-1=0$$ $$x=1$$
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