## Intermediate Algebra (6th Edition)

$$x=-\frac{1}{3}$$ $$x=-\frac{2}{7}$$
We have $$(1-x)(3x+2)=-4x$$ Solving for the first parenthesis $$1-x = -4x$$ $$-x+4x=-1$$ $$3x=-1$$ $$x=-\frac{1}{3}$$ Solving for the second parenthesis $$3x+2=-4x$$ $$3x+4x=-2$$ $$7x=-2$$ $$x=-\frac{2}{7}$$