Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 36

Answer

$2y^{x-7}$

Work Step by Step

Using laws of exponents, the given expression, $ \dfrac{4y^{3x-3}}{2y^{2x+4}} $, simplifies to \begin{array}{l} 2y^{3x-3-(2x+4)} \\\\ 2y^{3x-3-2x-4} \\\\ 2y^{x-7} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.