Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 26



Work Step by Step

$(8^{6})^{-3}=8^{6\times-3}=8^{-18}=\frac{1}{8^{18}}$ In general, $(a^{m})^{n}=a^{m\times n}$
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