Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 29

Answer

$\dfrac{1}{4p^{4}}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \left( \dfrac{8p^6}{4p^4} \right)^{-2} \\\\= \left( 2p^{6-4} \right)^{-2} \\\\= \left( 2p^{2} \right)^{-2} \\\\= 2^{-2}p^{2(-2)} \\\\= 2^{-2}p^{-4} \\\\= \dfrac{1}{2^{2}p^{4}} \\\\= \dfrac{1}{4p^{4}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.