Answer
$\frac{1}{16x^{2}}$
Work Step by Step
$(-4x)^{-2}=\frac{1}{(-4x)^{2}}=\frac{1}{(-4\times-4)\times(x^{1+1})}=\frac{1}{16x^{2}}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Review - Page 329: 24
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