Answer
$\dfrac{xz}{4}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
\dfrac{4^{-1}x^{3}yz}{x^{-2}yx^{4}}
\\\\=
\dfrac{x^{3}yz}{4x^{-2+4}y}
\\\\=
\dfrac{x^{3}yz}{4x^{2}y}
\\\\=
\dfrac{x^{3-2}y^{1-1}z}{4}
\\\\=
\dfrac{xz}{4}
.\end{array}
