Answer
$27x^{19a}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
x^{4a}(3x^{5a})^3
\\\\=
x^{4a}(3^3x^{5a(3)})
\\\\=
x^{4a}(27x^{15a})
\\\\=
27x^{4a+15a}
\\\\=
27x^{19a}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Review - Page 329: 35
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