Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 9

$(\frac{3}{2},1)$

$2x+5y = 8$ Equation $(1)$ $6x+y = 10$ Equation $(2)$ Multiply Equation $(1)$ by $-3$ $-6x-15y = -24$ Equation $(3)$ Add Equations $(3)$ and $(2)$ to eliminate $x$ $-6x+6x-15y+y = -24+10$ $-14y=-14$ $y=1$ Substituting $y$ value in Equation$(2)$, $6x+y=10$ $6x+1 = 10$ $6x = 10-1$ $6x = 9$ $x=\frac{9}{6}$ $x=\frac{3}{2}$ Solution: $(\frac{3}{2},1)$