Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 8

Answer

Solution: $(5,2)$

Work Step by Step

$2x-y=8$ Equation $(1)$ $x+3y=11$ Equation $(2)$ Solving by elimination method. Multiply Equation $(1)$ by $3$ $6x-3y=24$ Equation $(3)$ Add Equations $(3)$ and $(2)$ to eliminate $y$ $6x-3y+x+3y = 24 +11$ $7x = 35$ $x= 5$ Substituting $x$ value in Equation$(2)$, we get $x+3y=11$ $5+3y=11$ $3y=11-5$ $3y=6$ $y=\frac{6}{3}=2$ Solution: $(5,2)$
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