Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 12

Answer

Solution set is $\{ (x,y) | 2x-5y=3\}$ or $\{ (x,y) | -4x+10y = -6\}$

Work Step by Step

$2x-5y = 3$ Equation $(1)$ $-4x+10y = -6$ Equation $(2)$ Multiply Equation $(1)$ by $2$ $4x-10y = 6$ Equation $(3)$ Adding Equation $(2)$ and Equation $(3)$ $-4x+4x+10y-10y = -6 +6$ $0=0$ This resulting statement is true for all possible values of $x$ or $y$. The equations have infinite number of solutions. Solution set is $\{ (x,y) | 2x-5y=3\}$ or $\{ (x,y) | -4x+10y = -6\}$
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