Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 15

Answer

Solution: $(-1,3,2)$

Work Step by Step

$x+y = 2$ Equation $(1)$ $-3y +z = -7$ Equation $(2)$ $2x+y-z = -1$ Equation $(3)$ Adding Equation $(2)$ and Equation $(3)$ $2x-3y+y+z-z = -8$ $2x-2y = -8$ Divide both sides by $2$ $x-y = -4$ Equation $(4)$ Adding Equation $(1)$ and Equation $(4)$ $x+x+y-y = 2-4$ $2x = -2$ $x= -1$ Substituting $x$ value in Equation $(1)$ $x+y = 2$ $-1+y = 2$ $y = 3$ Substituting $y$ value in Equation $(2)$ $-3y +z = -7$ $-3(3)+z = -7$ $-9 +z = -7$ $z = -7 +9$ $z = 2$ $x= -1$ $y = 3$ $z = 2$ Solution: $(-1,3,2)$
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