Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 13

Answer

Solution: $(1,\frac{1}{3})$

Work Step by Step

$y = \frac{1}{3} x$ Equation $(1)$ $5x-3y = 4$ Equation $(2)$ Substituting $y$ from Equation $(1)$ in Equation $(2)$ $5x - 3 (\frac{1}{3}x) = 4$ $5x -x = 4$ $4x = 4$ $x = 1$ Substituting $x$ value in Equation $(1)$ $y = \frac{1}{3} x$ $y = \frac{1}{3} (1)$ $y = \frac{1}{3} $ Solution: $(1,\frac{1}{3})$
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