Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 10

Answer

Solution: $(-2,\frac{3}{4})$

Work Step by Step

$\frac{1}{8}x-\frac{1}{2}y=\frac{-5}{8}$ Equation $(1)$ $-3x-8y=0$ Equation $(2)$ Multiply Equation $(1)$ by LCD $8$ to eliminate fractions. $8(\frac{1}{8}x-\frac{1}{2}y)=8(\frac{-5}{8})$ $8(\frac{1}{8}x)-8(\frac{1}{2}y)=8(\frac{-5}{8})$ $x-4y=-5$ Equation $(3)$ Multiply Equation $(3)$ by 3 and add with Equation $(2)$ to eliminate $x$. $3(x-4y) -3x-8y =-5 \times 3 + 0$ $3x-12y -3x -8y = -15$ $-20y = -15$ $y = \frac{-15}{-20} = \frac{3}{4}$ Substituting $y$ value in Equation $(2)$ $-3x-8y=0$ $-3x-8(\frac{3}{4})=0$ $-3x-6=0$ $-3x=6$ $x=-2$ Solution: $(-2,\frac{3}{4})$
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