## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 51

#### Answer

a=$\frac{4}{5}$

#### Work Step by Step

Original Equation $\frac{1}{4}$(a+2)=$\frac{1}{6}$(5-a) Multiply both sides by 12 3(a+2)=2(5-a) Distribute 3a+6=10-2a Add 2a and subtract 6 from both sides 5a=4 Divide both sides by 5 a=$\frac{4}{5}$

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