Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 55: 35

Answer

All real numbers

Work Step by Step

Original Equation 4(n+3)=2(6+2n) Distribute 4n+12=12+4n Subtract 4n+12 from both sides 0=0 Because both sides of the equation canceled each other out, this means that both sides of the equations are equal to each other. Therefore, the solution to this equation is all real numbers.
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