Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 55: 15



Work Step by Step

We are given that $8x-5x+3=x-7+10$. In order to solve for x, we can first group like terms on each side. $3x+3=x+3$ Subtract x from both sides. $2x+3=3$ Subtract 3 from both sides. $2x=0$ Divide both sides by 2. $x=0$
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