Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 55: 21



Work Step by Step

We are given that $-2(5y-1)-y=-4(y-3)$. In order to solve for y, we can first use the distributive property to simplify both sides. $-2\times(5y-1)-y=-4\times(y-3)$ $-10y+2-y=-4y+12$ Group like terms on the left side. $-11y+2=-4y+12$ Add 11y to both sides. $2=7y+12$ Subtract 12 from both sides. $-10=7y$ Divide both sides by 7. $y=-\frac{10}{7}$
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