Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set - Page 55: 11



Work Step by Step

We are given the equation $5y+12=2y-3$. We can solve for y by first adding 3 to both sides. $5y+15=2y$ Subtract 5y from both sides. $15=-3y$ Divide both sides by -3. $y=-5$
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