Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 3



Work Step by Step

To solve for $x$ in the equation $-10=x+12$, you need only to subtract 12 from both sides to get $x$ by itself. $-10-12=(x+12)-12$ Therefore, $-22=x$
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