Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.4 - Partial Sums of Arithmetic and Geometric Sequences - Exercise Set - Page 659: 48

Answer

The total number of new customers attracted during the first 5 days is 800.

Work Step by Step

For this arithmetic sequence, we have $a_{1} = 80$ and $d = 40$, the general term $a_{n} = 80 + (n - 1)(40)$ where n is the number of days. The total number of new customers attracted during the first 5 days is $\sum\limits_{n = 1}^5 a_{n} = \sum\limits_{n = 1}^5 [80 + (n - 1)(40)]$ = $\frac{5(80 + a_{5})}{2}$ = $\frac{5(80 + 240)}{2}$ ($\because$ $a_{5}$ = 80+(5-1)(40) = 240) = 800 new customers
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