Answer
$S_{15}=-495$
Work Step by Step
Using $S_{n}=\dfrac{n}{2}(2a_1+(n-1)d)$, the sum of the first $
15
$ terms of the sequence $
-5,-9,-13,...,-61
$ is
\begin{array}{l}
S_{15}=\dfrac{15}{2}\left(2(-5)+(15-1)(-4)\right)\\\\
S_{15}=\dfrac{15}{2}\left(-10+-56\right)\\\\
S_{15}=\dfrac{15}{2}\left(-66\right)\\\\
S_{15}=-495
.\end{array}