Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.4 - Partial Sums of Arithmetic and Geometric Sequences - Exercise Set - Page 659: 37

Answer

The money she made during her fourth year of business (n = 4) is $\$39,930$ Her total earnings during the first four years is $\$139,230$

Work Step by Step

The situation can be represented by a geometric series with $a_{1} = \$30000$ and $r = (1 + 10\%) = 1.1$ including the initial amount made in the first year, which the general term is $a_{n} = 30000(1.1)^{n-1}$ and $n$ is the number of year The money she made during her fourth year of business (n = 4) is $a_{4} = 30000(1.1)^{4-1} = \$39,930$ Her total earnings during the first four years is $\sum\limits_{n=1}^4 a_{n} = \sum\limits_{n=1}^4 30000(1.1)^{n-1}$ = $\frac{30000(1 - 1.1^4)}{(1 - 1.1)}$ = $\$139,230$
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