Answer
The total number of revolutions made before the flywheel comes to rest is 500.
Work Step by Step
The situation can be modeled by an infinite geometric sequence, with $a_{1} = 300$ and $r = \frac{2}{5}$, which the general term $a_{n} = 300(\frac{2}{5})^{n-1}$ where n is the number of minutes.
The total number of revolutions made before the flywheel comes to rest is
= $\sum\limits_{n=1}^{\infty} a_{n} = \sum\limits_{n=1}^{\infty} 300(\frac{2}{5})^{n-1}$
= $\frac{300}{1 - \frac{2}{5}}$
= 500 revolutions
