Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.4 - Partial Sums of Arithmetic and Geometric Sequences - Exercise Set - Page 659: 35

Answer

254,000

Work Step by Step

We are asked to find the 10th term. The equation for the 10th term is: $$a_{10}=a_1+(10-1)d$$ Where d is the common difference. From this, we have: $$S_{10}=10/2(a_1+a_{10})$$ Substituting, we have: $$S_{10}=10/2(a_1+(a_1+(10-1)d))$$ We substitute the values to get 254,000
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