Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 62

Answer

135 feet

Work Step by Step

We know that the distance the ball travels is given by the following expression: $$2\times \sum _{n=1}^{\infty }(15)(.8^n)$$ Note, we multiply by 2 since the ball bounces down and then goes up for each bounce. Simplifying: $$ = 15(5-0.8^0)\times 2 \\ = 120 $$ Adding the initial 15 foot drop, the total is: $$ =120+15 \\ =135 \ ft$$
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