Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 49

Answer

$S_{30}=900$

Work Step by Step

The sequence consisting of the first 30 odd positive integers has $a_1=1$ and $d=2$. Using $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$, then, \begin{array}{l} S_{30}=\dfrac{30}{2}(2\cdot1+(30-1)2)\\ S_{30}=15(2+58)\\ S_{30}=15(60)\\ S_{30}=900 .\end{array}
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