Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 50

Answer

$S_{20}=1,470$

Work Step by Step

The sequence consisting of the first 20 positive multiples of 7 has $a_1=7$ and $d=7$. Using $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$, then, \begin{array}{l} S_{20}=\dfrac{20}{2}(2\cdot7+(20-1)7)\\ S_{20}=10(14+133)\\ S_{20}=10(147)\\ S_{20}=1,470 .\end{array}
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