Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 42

Answer

25 pounds of decay 175 pounds of decay in the first three years

Work Step by Step

$a_n = 200*.5^n$ $n=3$ $a_n = 200*.5^n$ $a_3 = 200*.5^3$ $a_3=200*.125$ $a_3=2*12.5$ $a_3=25$ 25 pounds of decay First three years: $n=1$ $a_n = 200*.5^n$ $a_1 = 200*.5^1$ $a_1=200*.5$ $a_1=100$ $n=2$ $a_n = 200*.5^n$ $a_2 = 200*.5^2$ $a_2=200*.25$ $a_2=50$ $100+50+25=175$ 175 pounds of decay in the first three years
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