Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 44

Answer

$91$

Work Step by Step

Using the given general term, $ a_n=n^2 ,$ then, \begin{array}{l} a_1=(1)^2\\ a_1=1 ,\\\\ a_2=(2)^2\\ a_2=4 ,\\\\ a_3=(3)^2\\ a_3=9 ,\\\\ a_4=(4)^2\\ a_4=16 ,\\\\ a_5=(5)^2\\ a_5=25 ,\\\\ a_6=(6)^2\\ a_6=36 .\end{array} Hence, $ S_6=1+4+9+16+25+36 = 91 .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.