Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 52

Answer

$S_8=2,460$

Work Step by Step

The sequence $ \dfrac{3}{4},\dfrac{9}{4},\dfrac{27}{4},... $ is a geometric sequence with $a_1=\dfrac{3}{4}$ and $r=3$. Using $S_n=\dfrac{a_1(1-r^n)}{1-r}$, then, \begin{array}{l} S_8=\dfrac{\dfrac{3}{4}(1-3^8)}{1-3}\\\\ S_8=\dfrac{\dfrac{3}{4}(-6,560)}{-2}\\\\ S_8=2,460 .\end{array}
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