Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.6 - Exponential and Logarithmic Equations; Further Applications - 9.6 Exercises - Page 630: 6

Answer

0.792

Work Step by Step

We are given the equation $4^{x}=3$. In order to solve, we must first take the natural log of both sides. $ln(4^{x})=ln(3)$ $xln(4)=ln(3)$ Divide both sides by $ln(4)$. $x=\frac{ln(3)}{ln(4)}\approx0.792$
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