## Intermediate Algebra (12th Edition)

We are given the equation $4^{x}=3$. In order to solve, we must first take the natural log of both sides. $ln(4^{x})=ln(3)$ $xln(4)=ln(3)$ Divide both sides by $ln(4)$. $x=\frac{ln(3)}{ln(4)}\approx0.792$