Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.6 - Exponential and Logarithmic Equations; Further Applications - 9.6 Exercises - Page 630: 30

Answer

$x=23$

Work Step by Step

Since $\log_b y=x$ implies $y=b^x$, the given equation, $ \log_5(5x+10)=3 $, implies \begin{align*}\require{cancel} 5x+10&=5^3 \\ 5x+10&=125 .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} 5x&=125-10 \\ 5x&=115 \\\\ \dfrac{\cancel5x}{\cancel5}&=\dfrac{115}{5} \\\\ x&=23 .\end{align*} Hence, the solution to the equation $ \log_5(5x+10)=3 $ is $ x=23 $.
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