Answer
NOT a one-to-one function
Work Step by Step
The given set of ordered pairs, $
\left\{(-1,3)(2,7),(4,3),\left(5,8\right)\right\}
$, has $y$-values that repeat (i.e. $3$ is paired with $-1$ and $4$). Hence, the function with the given set of ordered pairs is NOT a one-to-one function.