Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Summary Exercises - Applying Methods for Solving Quadratic Equations - Page 531: 7

Answer

$\left\{-\sqrt{7},\sqrt{7}\right\}$

Work Step by Step

Taking the square root of both sides (Square Root Property), the given equation, $ p^2=7 ,$ is equivalent to \begin{align*} p=\pm\sqrt{7} .\end{align*} Hence, the solution set of the equation $ p^2=7 $ is $\left\{-\sqrt{7},\sqrt{7}\right\}$.
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