Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Summary Exercises - Applying Methods for Solving Quadratic Equations - Page 531: 23

Answer

$t=\dfrac{3}{2}$

Work Step by Step

Using factoring of trinomials, the given equation, $ 4t^2-12t+9=0 ,$is equivalent to \begin{align*} (2t-3)(2t-3)&=0 \\ (2t-3)^2&=0 .\end{align*} Taking the square root of both sides (Square Root Property) and solving for the variable, the equation above is equivalent to \begin{align*} 2t-3&=\pm\sqrt{0} \\ 2t-3&=0 \\ 2t&=3 \\ t&=\dfrac{3}{2} .\end{align*} Hence, the solution of the equation $ 4t^2-12t+9=0 $ is $t=\dfrac{3}{2}$.
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