Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Summary Exercises - Applying Methods for Solving Quadratic Equations - Page 531: 15

Answer

$\left\{\dfrac{1}{2},2\right\}$

Work Step by Step

Squaring both sides, the given equation, $ x\sqrt{2}=\sqrt{5x-2} ,$ is equivalent to \begin{align*} \left(x\sqrt{2}\right)^2&=\left(\sqrt{5x-2}\right)^2 \\ x^2(2)&=5x-2 \\ 2x^2&=5x-2 \\ 2x^2-5x+2&=0 .\end{align*} Using factoring of trinomials, the equation above is equivalent to \begin{align*} (x-2)(2x-1)&=0 .\end{align*} Equating each factor to zero (Zero Product Property) and solving for the variable, then \begin{array}{l|r} x-2=0 & 2x-1=0 \\ x=2 & 2x=1 \\\\ & x=\dfrac{1}{2} .\end{array} Hence, the solution set of the equation $ x\sqrt{2}=\sqrt{5x-2} $ is $\left\{\dfrac{1}{2},2\right\}$.
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