Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Summary Exercises - Applying Methods for Solving Quadratic Equations - Page 531: 28

Answer

$\left\{-13,13\right\}$

Work Step by Step

Taking the square root of both sides (Square Root Property), the given equation, $ w^2=169 ,$ is equivalent to \begin{align*} w&=\pm\sqrt{169} \\&= \pm13 .\end{align*} Hence, the solution set of the equation $ w^2=169 $ is $\left\{-13,13\right\}$.
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