#### Answer

F. $\sqrt 6$

#### Work Step by Step

As shown on page 445, we know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$.
Therefore, $6^{\frac{2}{4}}=6^{\frac{2\div2}{4\div2}}=6^{\frac{1}{2}}=\sqrt[2] 6^{1}=\sqrt 6$.

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

F. $\sqrt 6$

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