Answer
-8
Work Step by Step
As shown on page 445, we know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$.
Therefore, $-32^{\frac{3}{5}}=-(\sqrt[5] 32^{3})=-((\sqrt[5] 32)^{3})=-(2^{3})=-(8)=-8$.
We know that $\sqrt[5] 32=2$, because $2^{5}=32$.