Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.2 - Rational Exponents - 7.2 Exercises - Page 448: 33

Answer

$\frac{1}{512}$

Work Step by Step

We know that $a^{-\frac{m}{n}}=\frac{1}{a^{\frac{m}{n}}}$, where $a^{\frac{m}{n}}$ is a real number. Therefore, $64^{-\frac{3}{2}}=\frac{1}{64^{\frac{3}{2}}}$. We know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=\sqrt[n] (a)^{m}$, where all indicated roots are real numbers. Therefore, $\frac{1}{64^{\frac{3}{2}}}=\frac{1}{\sqrt 64^{3}}=\frac{1}{(\sqrt 64)^{3}}=\frac{1}{8^{3}}=\frac{1}{512}$. $\sqrt 64=8$, because $8^{2}=64$
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