## Intermediate Algebra (12th Edition)

As shown on page 445, we know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$. Therefore, $625^{\frac{1}{4}}=\sqrt[4] 625^{1}=\sqrt[4] 625=5$. We know that $\sqrt[4] 625=5$, because $5^{4}=625$.