#### Answer

9

#### Work Step by Step

As shown on page 445, we know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$.
Therefore, $729^{\frac{1}{3}}=\sqrt[3] 729^{1}=\sqrt[3] 729=9$.
We know that $\sqrt[3] 729=9$, because $9^{3}=729$.

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

9

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