#### Answer

$\frac{x-3}{x+1}$

#### Work Step by Step

$\frac{x^{2}+2x-15}{x^{2}+6x+5}=\frac{(x+5)(x-3)}{(x+5)(x+1)}=\frac{x-3}{x+1}\times\frac{x+5}{x+5}=\frac{x-3}{x+1}\times1=\frac{x-3}{x+1}$

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

$\frac{x-3}{x+1}$

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