Answer
$\frac{(x+3)}{2x(x-3)}$
Work Step by Step
$\frac{4x(x+3)}{8x^{2}(x-3)}=\frac{4x}{8x^{2}}\times\frac{(x+3)}{(x-3)}=\frac{1}{2x}\times\frac{(x+3)}{(x-3)}=\frac{(x+3)}{2x(x-3)}$
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