#### Answer

$\frac{x}{8}$

#### Work Step by Step

$\frac{2x^{2}-5x}{16x-40}=\frac{x(2x-5)}{8(2x-5)}=\frac{x}{8}\times\frac{(2x-5)}{(2x-5)}=\frac{x}{8}\times1=\frac{x}{8}$

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

$\frac{x}{8}$

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