#### Answer

$\frac{6}{7}$

#### Work Step by Step

$\frac{6m+18}{7m+21}=\frac{6(m+3)}{7(m+3)}=\frac{6}{7}\times\frac{(m+3)}{(m+3)}=\frac{6}{7}\times1=\frac{6}{7}$

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

$\frac{6}{7}$

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