Answer
$\frac{2}{t-3}$
Work Step by Step
$\frac{2t+6}{t^{2}-9}=\frac{2(t+3)}{(t+3)(t-3)}=\frac{2}{t-3}\times\frac{t+3}{t+3}=\frac{2}{t-3}\times1=\frac{2}{t-3}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - 6.1 Exercises - Page 374: 41
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